<math>\forall i, j, \forall s_k, s_m \in A_i, p(s^{(t)} \in A_j | s^{(t-1)} = s_k) = p(s^{(t)} \in A_j | s^{(t-1)} = s_m)</math>,其中,<math>p(s^{(t)} \in A_j | s^{(t-1)} = s_k) = \sum_{s_m \in A_j} p(s^{(t)} = s_m | s^{(t-1)} = s_k)</math> | <math>\forall i, j, \forall s_k, s_m \in A_i, p(s^{(t)} \in A_j | s^{(t-1)} = s_k) = p(s^{(t)} \in A_j | s^{(t-1)} = s_m)</math>,其中,<math>p(s^{(t)} \in A_j | s^{(t-1)} = s_k) = \sum_{s_m \in A_j} p(s^{(t)} = s_m | s^{(t-1)} = s_k)</math> |