更改

</math>

</math>

|{{EquationRef|1}}}}

|{{EquationRef|1}}}}

其中<math>f\left(x^{*}, r_{c}\right)=0</math>。又由于鞍结点分岔的在分岔点<math>(x^*, r_c)</math>处有<math>\left. \frac {\partial f}{\partial x}\right|_{\left(x^{*} ; r_{c}\right)}=0</math>，再将<math>\left. \frac {\partial f}{\partial r}\right|_{\left(x ; r_{c}\right)}</math>视为常数<math>a</math>，将<math>\left. \frac {1}{2} \frac{\partial^{2} f}{\partial x^{2}}\right|_{\left(x ; r_{c}\right)}</math>视为常数<math>b</math>。忽略后面的高阶项，即可得到<math>\dot{x} = a(r-r_c)+b(x-x^*)^2</math>

其中<math>f\left(x^{*}, r_{c}\right)=0</math>。又由于鞍结点分岔在分岔点<math>(x^*, r_c)</math>处有<math>\left. \frac {\partial f}{\partial x}\right|_{\left(x^{*} ; r_{c}\right)}=0</math>，再将<math>\left. \frac {\partial f}{\partial r}\right|_{\left(x ; r_{c}\right)}</math>视为常数<math>a</math>，将<math>\left. \frac {1}{2} \frac{\partial^{2} f}{\partial x^{2}}\right|_{\left(x ; r_{c}\right)}</math>视为常数<math>b</math>。忽略后面的高阶项，即可得到<math>\dot{x} = a(r-r_c)+b(x-x^*)^2</math>

===例子===

===例子===