\sum_{i=1}^{N}(\frac{x_{i}^{\alpha}}{\sum_{j=1}^{N} x_{j}^{\alpha}})\cdot log x_{i}^{\alpha}\le log\sum_{i=1}^{N}(\frac{x_{i}^{\alpha}}{\sum_{j=1}^{N} x_{j}^{\alpha}}\cdot x_{i}^{\alpha}), | \sum_{i=1}^{N}(\frac{x_{i}^{\alpha}}{\sum_{j=1}^{N} x_{j}^{\alpha}})\cdot log x_{i}^{\alpha}\le log\sum_{i=1}^{N}(\frac{x_{i}^{\alpha}}{\sum_{j=1}^{N} x_{j}^{\alpha}}\cdot x_{i}^{\alpha}), |